Capacitor charge in series and parallel circuit

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Three capacitors (C1 = 4.0 μF, C2 = 3.0 μF, C3 = 2.0 μF) are connected to a 12-V source, with C2 and C3 in parallel and C1 in series with their combination. The charge on C2 cannot be calculated without first determining the equivalent capacitance of C2 and C3 together, as they share the same voltage. The initial approach mistakenly treated C1 and C2 as a series connection, leading to an incorrect charge calculation. To find the correct charge on C2, the total capacitance of C2 and C3 must be combined before considering the series connection with C1. Understanding the correct configuration is crucial for accurate charge determination.
Joshb60796
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Homework Statement



Three capacitors, with capacitances C1 = 4.0 μF, C2 = 3.0 μF, and C3 = 2.0 μF, are
connected to a 12 -V voltage source, as shown in the figure. What is the charge on
capacitor C2 ?

Homework Equations


Q=VC
Q = charge
V = voltage
C = capacitance
Ceq = equivalent capacitance

The Attempt at a Solution



C1 and C2 are in series and therefore should be summed as in Ceq=1/((1/C1)+(1/C2)) because the voltage across them will be shared proportionally. If I multiply Ceq by the voltage I get a charge of Q12 which is for both capacitors. I need to find the charge on C2 so I am multiplying the charge on both, Q12, by the proportion of C2 to C1 which is 3/4. I am getting 15.4 microCoulombs but my answer should come to 16 microCoulombs. I need help on this questions. Am I doing this correctly? Is my thought process correct?
 

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(try using the X2 button just above the Reply bos

Hi Joshb60796! :smile:

(try using the X2 button just above the Reply bos :wink:)
Joshb60796 said:
C1 and C2 are in series …

Nooo :redface:

C2 and C3 are in parallel, and then C1 is in series with their resultant.

Try again. :smile:
 
tiny-tim said:
Hi Joshb60796! :smile:

(try using the X2 button just above the Reply bos :wink:)


Nooo :redface:

C2 and C3 are in parallel, and then C1 is in series with their resultant.

Try again. :smile:


I was aware that C2 and C3 were parallel which is why I didn't include C3. Aren't C2 and C3 seeing the same voltage so if the voltage is connected for a long time C3 doesn't factor into the charge that is held on C2? I thought it was just Capacitance and Voltage that has to do with Charge, Q.
 
Joshb60796 said:
Aren't C2 and C3 seeing the same voltage …

yes :smile:
so if the voltage is connected for a long time C3 doesn't factor into the charge that is held on C2?

yes it does, C2 has to share its charge with C3 (and btw, not equally)
I thought it was just Capacitance and Voltage that has to do with Charge, Q.

yes, but you have to use the total capacitance of C2 and C3 combined to find how that combines with C1 :wink:

find the capacitance of C2 and C3,

then find the total capacitance …

show us what you get :smile:
 
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