Capacitors: find the dielectric constant

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Alice7979
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Homework Statement


A parallel plate capacitor has a capacitance of 7.8 μF when filled with a dielectric. The area of each plate is 1.5 m^2 and the separation between the plates is 1.3 x 10-5 m. What is the dielectric constant of the dielectric?

Homework Equations


C= (K(8.85E-12)A)/d

The Attempt at a Solution


K= (1.5(7.8E-6 F))/((8.85E-12)(1.3E-5)
=1.02E11
 
on Phys.org
Alice7979 said:

Homework Statement


A parallel plate capacitor has a capacitance of 7.8 μF when filled with a dielectric. The area of each plate is 1.5 m^2 and the separation between the plates is 1.3 x 10-5 m. What is the dielectric constant of the dielectric?

Homework Equations


C= (K(8.85E-12)A)/d

The Attempt at a Solution


K= (1.5(7.8E-6 F))/((8.85E-12)(1.3E-5)
=1.02E11

Your last expression is unclear because the parentheses do not work (I am assuming you forgot a closing parenthesis at the very end). Double check your algebra, it looks like you end up multiplying the capacitance by the area in finding K, which cannot be right.
 
Alice7979 said:

Homework Statement


A parallel plate capacitor has a capacitance of 7.8 μF when filled with a dielectric. The area of each plate is 1.5 m^2 and the separation between the plates is 1.3 x 10-5 m. What is the dielectric constant of the dielectric?

Homework Equations


C= (K(8.85E-12)A)/d

The Attempt at a Solution


K= (1.5(7.8E-6 F))/((8.85E-12)(1.3E-5)
=1.02E11

I had the area and length switched, thank you