Capaticance of thin spherical ball

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A thin spherical ball does have capacitance when a positive charge is placed nearby, due to the induced charge on its surface. To define this capacitance, a reference point is necessary, typically chosen at infinity where the potential is zero. The capacitance can be calculated using the formula C = Q / (φ(A) - φ(B)), where φ(A) is the potential on the surface of the ball and φ(B) is the potential at infinity. The concept of a giant spherical capacitor helps visualize this scenario, with the outer shell extending to infinity. Thus, the capacitance of the spherical ball can be derived by considering this reference point at infinity.
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suppose there is a uncharged thin spherical ball (thickness tends to 0) then Does if have any capacitance if a +q charge is placed near it?
 
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yes there will be an induced charge on the shell due to which there will be some capacitance
 
iitjee10 said:
yes there will be an induced charge on the shell due to which there will be some capacitance

ok! but capacitance is always b/w two quantities having a distance d.then for a sphere?
 
Yes, you need a reference point to specify the capacitance of the spherical ball, due to

C = \frac{Q}{\phi(A) - \phi(B)}

with \phi(A): potential on the surface of the ball; \phi(B): potential on the surface, the reference point is on

If the reference point is in infinity, we know that the potential in infinity must vanish, cause only in this case the energy is finite. So we can take B=\infty (imagine a giant spherical capacitor which outer shell is in infinity with the potential \phi(\infty)=0). In this term we can derive the capacitance of the spherical ball!
 
saunderson said:
Yes, you need a reference point to specify the capacitance of the spherical ball, due to

C = \frac{Q}{\phi(A) - \phi(B)}

with \phi(A): potential on the surface of the ball; \phi(B): potential on the surface, the reference point is on

If the reference point is in infinity, we know that the potential in infinity must vanish, cause only in this case the energy is finite. So we can take B=\infty (imagine a giant spherical capacitor which outer shell is in infinity with the potential \phi(\infty)=0). In this term we can derive the capacitance of the spherical ball!

i didn't get the phi(B)}[/tex]. which surface do you mention here??
 
astro2cosmos said:
i didn't get the phi(B)}[/tex]. which surface do you mention here??

This surface is in infinity ! Like I've said, imagine a giant spherical capacitor, with the inner shell of radius R1="radius of your spherical ball" and the the outer shell R_2 \rightarrow \infty... kind of hard to imagine, but if you don't have a reference point take it in infinity, cause there is always zero potential.
 
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