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## Homework Statement

Given the following information, derive and expression to calculate the capillary depression of mercury in a glass tube given that:

Contact angle = 140 degrees

Surface tension 'Gamma' = 0.476 Nm^-1

Tube diameter = 1.0mm

Density of mercury 'rho' = 13.58x10^3 kgm^-3 (ie. >> 'rho_0')

## Homework Equations

I've derived the following equation for capillary, which I think is correct:

[tex]

h=\frac{2\gamma cos \theta}{g(\rho -\rho_0)R}

[/tex]

So 'h' is the height of the mercury above the base of the tube.

## The Attempt at a Solution

But this gives me h= -1.095x10^-5 m. This doesn't seem like a correct value for 'h' even if I take it as possible, because it's even smaller than the tube diameter.

Also, the equation was derived by taking 'h' as the height from base to bottom of meniscus. I'm guessing the capillary depression is the distance between the bottom of the meniscus and the maximum height of the fluid (ie. radius of the meniscus). How do I calculate this using the equation I derived? I can only get 'h'.