A glass capillary sealed at the upper end is of length 0.11m and internal diameter 2 x 10^-5 m. The tube is immersed vertically into a liquid of surface tension 5.06 x 10^-2 N/m. To what length has the capillary to be immersed so that the liquid level inside and outside the capillary becomes the same? What will happen to the water level inside the capillary if the seal is now broken?
The Attempt at a Solution
Let A be the area of cross section of the tube. Initially, the volume of air inside the tube is AL. Here pressure is Patm.
Where L is the length of the tube.
When is it dipped, capillary rise takes place till some height.
Let it be dipped through a distance 'x' when the level of water equalises outside level. Volume of air present= A(L-x)
I don't know what will be the pressure at this stage. Is it equal to Patm?
When the seal is broken, the water will rise upwards and adjust its meniscus ( I calculated the capillary rise as 1.03m). What is the formula for the radius of meniscus?