Car A is starting from rest and accelerating at 4.0 m/s^2, car B passes it

AI Thread Summary
Car A accelerates from rest at 4.0 m/s², while Car B travels at a constant speed of 28 m/s. To determine when Car A catches up to Car B, the equations of motion for both cars are set equal. The resulting equation simplifies to 2t² - 28t = 0, leading to a solution of t = 14 seconds. The calculations and the final result are confirmed to be correct.
dasz
Messages
1
Reaction score
0

Homework Statement


Car A is starting from rest and accelerating at 4.0 m/s^2, car B passes it, moving at a constant speed of 28 m/s. How long will it take car A to catch up with car B.

Homework Equations



d=Vot+1/at^2

The Attempt at a Solution



Using the equation above, I used it for car A then car B and made them equal to each other. Got 2t^2 - 28t = 0 then solved. I got t= 14s.

Are there any mistakes? Thanks so much.[/B]
 
Physics news on Phys.org
Your equation and result look fine.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top