Carnot cycles in thermodynamics

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SUMMARY

The discussion centers on calculating the efficiency of a heat engine operating in a Carnot cycle between temperatures of 75.0°C and 353°C, absorbing 21,000 J of energy per cycle from the hot reservoir. The efficiency can be determined using the formula for Carnot efficiency, which is based on the temperatures of the hot and cold reservoirs. The cycle duration is noted as 2.00 seconds, but the primary focus is on the efficiency calculation rather than the work done or other parameters.

PREREQUISITES
  • Understanding of Carnot cycles in thermodynamics
  • Knowledge of temperature conversion from Celsius to Kelvin
  • Familiarity with the first law of thermodynamics
  • Ability to apply efficiency formulas in thermodynamic systems
NEXT STEPS
  • Research the Carnot efficiency formula: η = 1 - (Tc/Th)
  • Learn about the implications of temperature differences on engine efficiency
  • Explore the concept of work done in thermodynamic cycles
  • Study real-world applications of Carnot cycles in heat engines
USEFUL FOR

Students studying thermodynamics, engineers designing heat engines, and anyone interested in the principles of energy conversion and efficiency in thermal systems.

ndavis
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Homework Statement


A heat engine operates in a Carnot cycle between 75.0°C and 353°C. It absorbs 21000 J of energy per cycle from the hot reservoir. The duration of each cycle is 2.00 s.


Homework Equations


W=Qc-Qh, W=-P change in temperature

The Attempt at a Solution


I attempted to solve by converting celsius to kelvins,then finding the percent
 
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You never actually said what the problem asked for. Is it just the efficiency?
 

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