Cars A and B are d=60m apart and travelling at u(A)=8.8

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SUMMARY

The discussion centers on calculating the uniform deceleration of car A, which is initially traveling at 8.89 m/s while car B travels at 6.67 m/s, with a distance of 60 meters between them. After 45 seconds, car A applies the brakes to avoid colliding with car B, resulting in a collision. The calculated uniform deceleration of car A is definitively 0.0395 m/s². The participants utilized the equation of motion s = ut + 1/2at² to derive the solution.

PREREQUISITES
  • Understanding of kinematics equations, specifically s = ut + 1/2at²
  • Basic knowledge of uniform acceleration and deceleration concepts
  • Familiarity with relative motion in physics
  • Ability to solve algebraic equations involving motion
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  • Study the application of kinematic equations in collision scenarios
  • Learn about relative velocity and its impact on collision outcomes
  • Explore advanced topics in dynamics, such as friction and braking distance
  • Investigate real-world applications of deceleration calculations in automotive safety
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This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicle motion and collision avoidance strategies.

teng125
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cars A and B are d=60m apart and traveling at u(A)=8.89 and u(B)=6.67.knowing that 45s after driver A apply his brake to avoid overtaking B,the two cars collide,determine the uniform deceleration of car A.
i have tried to form eqns using s=ut + 1/2a(t^2) for both cars and substitute into [car A-car B=60] and can't find the answer.
the answer is 0.0395.
pls help...thanx...
 
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