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I Cart with Pendulum | Tension expression

  1. Sep 28, 2016 #1


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    I am trying to derive an expression for the Tension T in the massless bar in the given photo. Where there is a cart that is moving only in the x-direction and the bar is rotating around a point pivoted at the cart with angle theta. The expression that I have is deduced from:

    ∑ F (towards center) = Centripetal Acceleration

    Which gives:

    T - mg*cos(θ) = m * (θ (dot))2 *L

    Is this true? or I should add another force term that comes from the cart acceleration it self:
    M*x(double dot) * sin(θ)?


    Attached Files:

  2. jcsd
  3. Sep 30, 2016 #2


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    You have not stated the whole problem. From the diagram, it looks as though the cart is accelerating, or at least, free to accelerate in response to the tension.
    If you think of the bob's acceleration as that plus acceleration relative to the cart, the latter is the centripetal acceleration, yes? But the acceleration of the cart has a component in the radial direction, so it would not be true that the centripetal acceleration can be found by summing the radial components of the forces.
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