- #1
Gavins
- 27
- 0
Homework Statement
Suppose f is a holomorphic function on U = C - {0} and that
[tex]| f(z) | \leq | z |^{\frac{1}{2}} [/tex]
for all z in U. Show that f is everywhere zero.
Homework Equations
That question is supposed to require Cauchy's Integral Formula.
The Attempt at a Solution
Choose R>0 and take points a in the disc D(0,R) such that by Cauchy's Integral Formula,
[tex] |f(a)| = | \frac{1}{2\pi i} \int_{\partial D} \frac{f(z)}{z-a} dz| \leq \max |\frac{f(z)}{z-a}| 2\pi R[/tex]
I'm stuck on finding the max. I'm guessng I use the assumption but some help would be good. Thanks.
Last edited: