Celestial Die Hards: Escape Velocity at 1 Planck Length

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Escape velocity at 1 Planck length from an event horizon can be approximated using the equation for gamma, γ, which relates velocity to mass and distance. The discussion suggests that escape velocity varies with mass, and a simplified equation can be derived by letting R equal the Schwarzschild radius plus a small distance, d. The derived formula indicates that escape velocity approaches (1 - d/2R_s)c, where R_s is the Schwarzschild radius. The conversation emphasizes the use of Planck units for simplification, asserting G and c equal to 1. This analysis provides a theoretical framework for understanding escape velocity near black holes without considering rotating scenarios.
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What is escape velocity at 1 Planck length from an event horizon? Or, if it varies with the mass, is there a simple equation for computing the escape velocity? (No rotating black holes please, they hurt my brain).
 
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kjones000 said:
What is escape velocity at 1 Planck length from an event horizon? Or, if it varies with the mass, is there a simple equation for computing the escape velocity? (No rotating black holes please, they hurt my brain).

Well, I get that
\gamma = \frac{1}{\sqrt{1-(\frac{v}{c})^2}}}=\frac{1}{\sqrt{1-\frac{2GM}{c^2r}}}<br />

but I could use a double-check. Assuming this is right, if we let R = Rs +d, where Rs is the schwarzxshild radius 2GM/c^2, we can approximate this as

\gamma = \sqrt{\frac{2 G M}{d c^2}} = \sqrt{\frac{R_s}{d}}

this can be solved for v

v \approx (1 - \frac{d}{2 R_s})c

In Planck units, G=c=1
 
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