1. The problem statement, all variables and given/known data A partially loaded plane weighs 115,000 pounds. A famous actor's steamer trunk, weighing 300 pounds, is put into the rear cargo hold 250 inches behind the center of gravity. How much does this extra hold shift the center of gravity. 2. Relevant equations W1 = W x (L2 / L) W2 = W x (L1 / L) W = 115300 W1 = 115000 W2 = 300 L = 250 3. The attempt at a solution I did this: W2 = W x (L1 / L) so.... 300 = 115300 x (L1 / 250) so... 300 = 461.2L1 divide both sides by 461.2 L1 = .6504770165 The center of gravity of the plane shifts .6504770165 inches toward the rear. Your input is encouraged.