Center of mass of NH3 molecule, not quite there

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SUMMARY

The discussion focuses on calculating the center of mass of an ammonia (NH3) molecule, which consists of three hydrogen atoms forming an equilateral triangle and a nitrogen atom at the apex. The lengths between hydrogen atoms are 9.4x10^-11 meters, while the height from nitrogen to hydrogen is 10.14x10^-11 meters. The mass ratio used was 13.9 for nitrogen to hydrogen, but the correct periodic table values should be applied for accurate results. The participant's calculated y-coordinate of the center of mass was 3.125x10^-11 meters, while the correct value is 3.08x10^-11 meters, indicating a need for precise mass values in calculations.

PREREQUISITES
  • Understanding of molecular geometry, specifically pyramidal structures.
  • Familiarity with the Pythagorean theorem for height calculations.
  • Knowledge of mass ratios and their application in center of mass calculations.
  • Basic understanding of the periodic table for accurate atomic mass values.
NEXT STEPS
  • Research the accurate atomic masses of nitrogen and hydrogen from the periodic table.
  • Learn about the calculation of center of mass in three-dimensional structures.
  • Explore the implications of mass ratios in molecular physics.
  • Study examples of center of mass calculations for other molecular geometries.
USEFUL FOR

Students studying chemistry, particularly those focusing on molecular structure and physics, as well as educators teaching concepts related to molecular geometry and center of mass calculations.

1MileCrash
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Homework Statement



An amonia NH3 molecule in the figure has three hydrogen atoms, which form a equilateral triangle as the base of a pyramid. At the top of the pyramid is the nitrogen atom.

The length between any two hydrogen atoms is 9.4x10^-11, the length from nitrogen to any of the hydrogen atoms is 10.14x10^-11.

The mass ratio of nitrogen to hydrogen is 13.9.

The xaxis runs through the bottom of the pyramid, one of the points lies on it. The y-axis runs through the center of the pyramid vertically.

Homework Equations





The Attempt at a Solution



I am getting a close answer, but off enough to think I'm doing something wrong.

x center of mass is 0, by symmetry/intuition.

For y, what i did was try to find how high nitrogen is with the pythagorean theorem. I got that nitrogen should be at a height of 3.8x10^-11 along y axis.

I multiplied this number by 13.9, then divided by 16.9.


My result is 3.125x10^-11 for the ycom, but the correct answer is 3.08x10^-11. Why am I off by that amount?
 
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1MileCrash said:
For y, what i did was try to find how high nitrogen is with the pythagorean theorem. I got that nitrogen should be at a height of 3.8x10^-11 along y axis.
What triangle did you use?
 
The reason for the error is that I took their word for it and just used 1 and 13.9, while they used the actual periodic table masses of N and H. 13.9 is pretty darn close to the actual ratio of mass between the two, but not close enough.
 
Good. Glad you figured it out.
 

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