Center of Mass of open top cylinder

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SUMMARY

The discussion focuses on calculating the center of mass (CM) of a hollow cylindrical shell with a solid bottom and an open top, defined by radius R and height h. The initial approach incorrectly simplified the CM equation, leading to confusion about the correct placement of parentheses and signs. The correct formula for the CM is derived by considering the contributions from both the bottom and the missing top of the cylinder, ultimately clarifying that the CM is influenced by the solid bottom's position at height 0 and the open top's position at height h.

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naianator
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Homework Statement



The attached diagram shows a uniform density hollow cylindrical shell with a solid bottom and an open top. It has radius R and height h.

Find the height for the center of mass of this cylinder, taking the origin of the coordinate system at the center of the bottom. Use "pi" for π.

Homework Equations


x_cm=m_1x_1+m_2x_2+m_3x_3/m_1+m_2+m_3

The Attempt at a Solution


I'm not even really sure how to start but I tried this

If the top wasn't missing then the cylinder would have a center of mass at h/2 and the missing top has a center of mass at h so

CM = (h/2*(2*pi*R*h+2*pi*R^2)-h*pi*R^2)/2*pi*R*h+2*pi*R^2-pi*R^2

= pi*R*h^2/2*pi*R*h-pi*R^2
 

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If you had just the top piece located at height h, could you determine the center of its mass?
 
Borg said:
If you had just the top piece located at height h, could you determine the center of its mass?
Wouldn't it just be h?
 
naianator said:
Wouldn't it just be h?
And can you determine the mass of it?
 
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Borg said:
And can you determine the mass of it?
Wouldn't the masses cancel though? h = h*m/m?
 
naianator said:
CM = (h/2*(2*pi*R*h+2*pi*R^2)-h*pi*R^2)/2*pi*R*h+2*pi*R^2-pi*R^2

= pi*R*h^2/2*pi*R*h-pi*R^2
You really ought to parenthesise expressions correctly. You mean
(h/2*(2*pi*R*h+2*pi*R^2)-h*pi*R^2)/(2*pi*R*h+2*pi*R^2-pi*R^2)
or in LaTex
##\frac{\frac h2(2\pi Rh+2\pi R^2)-h\pi R^2}{2\pi Rh+2\pi R^2-\pi R^2}##
But you made a mistake in simplifying to
##\frac{\pi Rh^2}{2\pi R h-\pi R^2}##
(Note that that would make it > h/2.)
 
haruspex said:
You really ought to parenthesise expressions correctly. You mean
(h/2*(2*pi*R*h+2*pi*R^2)-h*pi*R^2)/(2*pi*R*h+2*pi*R^2-pi*R^2)
or in LaTex
##\frac{\frac h2(2\pi Rh+2\pi R^2)-h\pi R^2}{2\pi Rh+2\pi R^2-\pi R^2}##
But you made a mistake in simplifying to
##\frac{\pi Rh^2}{2\pi R h-\pi R^2}##
(Note that that would make it > h/2.)
I'm having trouble finding where the mistake is. Is the first expression correct?
 
naianator said:
I'm having trouble finding where the mistake is. Is the first expression correct?
Yes, it's just the last line that's wrong. Check the signs.
 
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haruspex said:
Yes, it's just the last line that's wrong. Check the signs.
Ahhh yes! Thank you
 
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naianator said:
If the top wasn't missing then the cylinder would have a center of mass at h/2 and the missing top has a center of mass at h so
Rather than that:

If both the top and bottom were missing, then the CM would be at h/2.

To this add in the bottom, which has CM at 0 .

It makes the algebra a bit easier.
 
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