Center of Mass: Weight Distribution for Bob & Charlie

AI Thread Summary
To determine the weight distribution between Bob and Charlie while carrying a 200 lb patient on a stretcher, the concept of torque is essential. The center of gravity is located 3 feet from Bob and 5 feet from Charlie, creating a torque balance around the center of gravity. By applying the torque equation, the forces exerted by Bob and Charlie can be calculated to ensure they equalize the torques about the center of gravity. This results in Bob supporting a greater portion of the weight due to the patient's position. Ultimately, the calculations reveal the precise weight each paramedic carries based on their distances from the center of gravity.
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Two paramedics, Bob and Charlie, carry a 200 lb patient on an 8-foot-long stretcher. Bob holds the front end of the stretcher and Charlie holds the back end. The patient lies closer to the front end of the stretcher, so his center of gravity is 3 feet from Bob's hands and 5 feet from Charlie's. How much of the patient's weight is carried by Bob and how much by Charlie?

where to start? what equation?
 
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HINT: Torque
 
The torques RXF about the cg must be equal in magnitude.
 

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