Centripetal Acceleration: Solving Physics Circular Motion

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The discussion revolves around a .10kg ball in vertical circular motion with a radius of .80 meters and a tangential velocity of 6.0 m/s at the top. The user questions their calculations, specifically whether the tangential velocity at the lowest point is 2.0 m/s and if the tension at the top is approximately 2.6 N. They used the conservation of energy principle (KE = PE) to find the velocity and applied the formula T = Fc + Fw to determine tension. The user notes a discrepancy, as their calculations show higher tension at the top compared to the bottom, prompting further clarification on the forces acting on the ball. The conversation highlights the complexities of centripetal acceleration and the interplay of kinetic and potential energy in circular motion.
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A .10kg ball is on a string in vertical circular motion with a radius .80 meters and the whole system is above the ground .20 meters At the top the tangential velocity is 6.0m/s.

I'm wondering if these are correct:
1)At the lowest point on the circular path the tangential velocity is 2.0 m/s.
2)The tension at the top of the circular path is ~2.6 N

I found the velocity by using KE = PE
I found the tension of the top by: T = Fc + Fw

The reason I'm wondering this is because I figured out the speed, and tensions on the top and bottom and I came up with a higher tension in the top than in the bottom...
 
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At the top, the tension and weight are acting in the same direction:
T + Fg = mv^2 / r
so then:
T= mv^2/r - Fg
 
In addition, for part A, the ball has both kinetic energy and gpe at the top, while at the bottom it should only have gpe.
 
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