- #1
nautica
a) A 22 kg child is riding a merry-go-round that is rotating at 40 rpm. What centripetal Force must she exert to stay on if she is 1.25 m from its center?
40 rpm = 4.19 rad/s
r = 1.25 m
Ac = (4.19 rad/s)^2 * (1.25 m) = 21.95 m/s^2
F = (22 kg) * ( 21.95 m/s^2) = 482.9 N
b) What cent Force does she need to stay on one that rotates at 3 rpm if she is 8 m from its center
3 rpm = .314 rad/s
Ac = (.314 rad/s)^2 (8 m) = .789 m/s^2
Force = (22 kg) (.789 m/s^2) = 17.36 N
c) compare each force with her weight.
Force 1 is 21.95 x's her weight
Force 2 is .789 x's her weight
how does this look
thank
nautica
40 rpm = 4.19 rad/s
r = 1.25 m
Ac = (4.19 rad/s)^2 * (1.25 m) = 21.95 m/s^2
F = (22 kg) * ( 21.95 m/s^2) = 482.9 N
b) What cent Force does she need to stay on one that rotates at 3 rpm if she is 8 m from its center
3 rpm = .314 rad/s
Ac = (.314 rad/s)^2 (8 m) = .789 m/s^2
Force = (22 kg) (.789 m/s^2) = 17.36 N
c) compare each force with her weight.
Force 1 is 21.95 x's her weight
Force 2 is .789 x's her weight
how does this look
thank
nautica
