Centripetal Ride: Chain Rated@3000N - Will it Hold?

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The discussion centers on determining if a chain rated at 3000N can support a chair and rider weighing 150kg, attached to a rotating tower. The calculations involve finding the net force (Fnet) by subtracting gravitational force (Fg) from the tension in the chain (Ft). The tension is calculated using the formula Ft = m*[v^2/r], where 'm' is mass, 'v' is velocity, and 'r' is radius. Participants confirm that the approach of comparing Fnet to the chain's rating is correct. The analysis aims to ensure the chain can withstand the forces generated during rotation.
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A chair is attached by a 9.0m long chain to the top of a tall rotating tower. The tower spins the chair and rider around at a rate of 1 Rev. every 4.0s. Max weight of the chair & rider is 150kg. You buy chain rated@3000N of tension. Will that chain be strong enough?
 
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Can you show some of your working? If you read the forum rules we will not do your homework for you.
 
A chair is attached by a 9.0m long chain to the top of a tall rotating tower. The tower spins the chair and rider around at a rate of 1 Rev. every 4.0s. Max weight of the chair & rider is 150kg. You buy chain rated@3000N of tension. Will that chain be strong enough?

I have the same problem as posted above. what i have come with so far is that Fnet = Ft-Fg. Where Ft is the tension in the chain. which i figure to be m*[v^2/r]. And Fg is gravity m*g. Then i simply subtracted them to get the Fnet. Then compared them to 3000N chain. Am I on the right track with the problem?
 
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