Centroid of a 3D Region using Triple Integral

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SUMMARY

The discussion focuses on calculating the centroid of a 3D region defined by the inequality x² + y² + z² ≤ k² with the constraint x ≥ 0, using triple integrals. The equations for the centroid coordinates are provided, specifically \overline{x}, \overline{y}, and \overline{z}, which require integration over the specified volume. The participant seeks guidance on determining the bounds of integration and suggests using spherical polar coordinates for the calculations. The volume element is defined as dv = r² sin(θ) dr dθ dφ.

PREREQUISITES
  • Understanding of triple integrals in multivariable calculus
  • Familiarity with spherical polar coordinates
  • Knowledge of centroid calculations in 3D space
  • Basic principles of volume integration
NEXT STEPS
  • Research the application of spherical coordinates in triple integrals
  • Study the derivation of bounds for integration in 3D regions
  • Explore examples of calculating centroids for various geometric shapes
  • Learn about volume elements in different coordinate systems
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Students and educators in mathematics, particularly those studying multivariable calculus, as well as professionals involved in engineering and physics who require knowledge of centroid calculations in three-dimensional spaces.

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Homework Statement


Compute the centroid of the region defined by x^{2} + y^{2} + z^{2} \leq k^{2} and x \geq 0 with \delta(x,y,z) = 1.

Homework Equations



\overline{x}=\frac{1}{m}\int\int\int x \delta(x,y,z) dV

\overline{y}=\frac{1}{m}\int\int\int y \delta(x,y,z) dV

\overline{z}=\frac{1}{m}\int\int\int z \delta(x,y,z) dV

The Attempt at a Solution


I understand that I need to integrate each of the above equations to get the x,y,z coordinates of the centroid, but how do I determine the bounds of integration?

Any help would be much appreciated! Thanks!
 
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I would use spherical polar co-ordinates.
<br /> \begin{array}{rcl}<br /> x &amp; = &amp; r\sin\theta\cos\varphi \\<br /> y &amp; = &amp; r\sin\theta\sin\varphi \\<br /> z &amp; = &amp; r\cos\theta<br /> \end{array}<br />

with dv=r^{2}\sin\theta drd\theta d\varphi
 

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