The discussion focuses on calculating average acceleration when a car changes direction from moving to the right to moving down, maintaining a constant speed of 5 m/s. The change in velocity (Δv) is calculated using the Pythagorean theorem, resulting in a magnitude of 5√2 m/s. The average acceleration is determined using the formula A = Δv/t, where t is 2 seconds, leading to an acceleration of 5√2 / 2 m/s². The direction of the average acceleration aligns with the direction of Δv, confirming its applicability in kinematic equations.
PREREQUISITESStudents studying physics, particularly those focusing on kinematics and motion analysis, as well as educators seeking to clarify concepts of acceleration and vector dynamics.
Looks good. But don't forget to attach the appropriate units.ahmed emad said:A=∆v/t so 5✓2 /2 , is that right?
Yes, the direction of the average acceleration will be in the direction of Δv.ahmed emad said:But is the direction of acceleraion will be the direction of ∆v?
What did you have in mind? Is there more to this problem? (Be careful not to apply formulas meant for 1D motion with constant acceleration.)ahmed emad said:And can I use kinimaticts fourmlas with this acceleration?