Change in Enthelpy when Internal Energy does not Change

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Luscinia
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Homework Statement



The internal energy of a perfect gas does not change when the gas undergoes isothermal expansion. What is the change in enthalpy?

Homework Equations


H=U+PV


The Attempt at a Solution


The answer is 0

Since U, the internal energy, doesn't change, I assumed that the equation would be ΔH=PΔV. Why would PΔV equal 0 if there is an expansion (ΔV is not 0)? I'm guessing that I'm not seeing something here since this seemed to be a rather simple question.
 
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The enthalpy is actually [itex]\Delta H = \Delta U + \Delta (PV)[/itex]. I don't think that PV will change.