Change in Enthelpy when Internal Energy does not Change

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SUMMARY

The change in enthalpy (ΔH) for a perfect gas undergoing isothermal expansion, where the internal energy (U) remains constant, is definitively zero. The equation for enthalpy, H = U + PV, indicates that if ΔU is zero, then ΔH must also be zero, regardless of the change in volume (ΔV). The confusion arises from the assumption that PΔV contributes to ΔH; however, since U does not change, the term Δ(PV) also remains unchanged, confirming that ΔH equals zero.

PREREQUISITES
  • Understanding of thermodynamic concepts, specifically enthalpy and internal energy.
  • Familiarity with the ideal gas law and its implications during isothermal processes.
  • Knowledge of the relationship between pressure, volume, and temperature in gases.
  • Basic proficiency in manipulating thermodynamic equations.
NEXT STEPS
  • Study the implications of isothermal processes on internal energy and enthalpy.
  • Learn about the ideal gas law and its applications in thermodynamics.
  • Explore the derivation of the enthalpy equation H = U + PV in detail.
  • Investigate real gas behavior versus ideal gas assumptions during thermodynamic processes.
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Students of thermodynamics, physics educators, and professionals in engineering fields focusing on gas behavior and energy transformations.

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Homework Statement



The internal energy of a perfect gas does not change when the gas undergoes isothermal expansion. What is the change in enthalpy?

Homework Equations


H=U+PV


The Attempt at a Solution


The answer is 0

Since U, the internal energy, doesn't change, I assumed that the equation would be ΔH=PΔV. Why would PΔV equal 0 if there is an expansion (ΔV is not 0)? I'm guessing that I'm not seeing something here since this seemed to be a rather simple question.
 
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The enthalpy is actually \Delta H = \Delta U + \Delta (PV). I don't think that PV will change.
 

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