Change in internal energy of a gas

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SUMMARY

The discussion focuses on calculating the change in internal energy (dU) of two moles of carbon monoxide (CO) during an adiabatic compression from a volume of 30 liters to 10 liters at an initial pressure of 1.2 atm. The relevant equations include the first law of thermodynamics, Q = dU + W, and the ideal gas law, PV = nRT. The specific heat capacity at constant pressure (Cp) is given as 29.16 J/(mol * K). The solution requires determining the initial temperature (T1) and the final temperature (T2) using the adiabatic process equation TV^γ = constant.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of adiabatic processes and the equation TV^γ = constant
  • Familiarity with the first law of thermodynamics (Q = dU + W)
  • Concept of specific heat capacity (Cp) for gases
NEXT STEPS
  • Calculate initial temperature (T1) using the ideal gas law with given pressure and volume
  • Determine final temperature (T2) using the adiabatic process equation TV^γ = constant
  • Calculate work done (W) during the adiabatic compression
  • Compute the change in internal energy (dU) using dU = nCpdT
USEFUL FOR

Students studying thermodynamics, particularly those focusing on gas laws and energy transformations in adiabatic processes.

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Homework Statement


Two moles of carbon monoxide (CO) start at a pressure of 1.2 atm and a volume of 30 liters. The gas is then compressed adiabatically to 1/3 this volume. Assume that the gas may be treated as ideal.

What is the change in the internal energy of the gas?

n = 1.2 atm
V2 = 10L
V1 = 30L
Cp = 29.16 J/(mol * K)

Homework Equations


Q = dU + W

The Attempt at a Solution


dU = dQ - dW
dU = nCpdT - pdV

dT is not known, and I can't go any further.
 
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You can find T_1 using PV = nRT. You can then use the adiabatic equation TV^{\gamma}= constant to find T_2
 

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