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## Homework Statement

Two moles of carbon monoxide (CO) start at a pressure of 1.2 atm and a volume of 30 liters. The gas is then compressed adiabatically to 1/3 this volume. Assume that the gas may be treated as ideal.

What is the change in the internal energy of the gas?

n = 1.2 atm

V2 = 10L

V1 = 30L

Cp = 29.16 J/(mol * K)

## Homework Equations

Q = dU + W

## The Attempt at a Solution

dU = dQ - dW

dU = nCpdT - pdV

dT is not known, and I can't go any further.