Change in Pressure: Find Gas P (Pa) Experiment

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Homework Help Overview

The discussion revolves around an experiment aimed at determining the specific heat of a gas using a water manometer. Participants are tasked with finding the change in pressure of the gas after heating, given an initial atmospheric pressure and a change in water levels in the manometer.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the equation ΔP = ρgΔh, with one attempting to calculate the change in pressure using a height difference of 4 cm. Others question the correctness of the calculations and the assumptions regarding the variables used in the equation.

Discussion Status

There is ongoing exploration of the calculations involved, with some participants expressing uncertainty about the results obtained and questioning whether any factors are being neglected. Guidance has been offered regarding the correct interpretation of variables and the importance of unit consistency.

Contextual Notes

Participants note the need to convert measurements from centimeters to meters and emphasize the significance of using the correct density of the fluid in the calculations. There is also mention of a discrepancy between calculated results and expected values from a reference source.

Devin Longo
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Homework Statement



An experiment to determine the specific heat of a gas makes use of a water manometer attached to a flask (the figure below ). Initially the two columns of water are even. Atmospheric pressure is 1.5 105 Pa. After heating the gas, the water levels change to those shown. Find the change in pressure of the gas in Pa.



2. Homework Equations
\DeltaP = \rhog\Deltah



The Attempt at a Solution



I basically did 1.5 x 10 ^5 * 9.8 m/s2 * .01m (what I assume given the picture to be the change in height)
 

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Difference in water level is 4 cm.
So ΔP = ρgΔh.
 
If I change 4 cm to meters I get 58800 as the calculated total from the equation, which is incorrect according to the website. Is there some factor I'm neglecting?
 
Devin Longo said:
If I change 4 cm to meters I get 58800 as the calculated total from the equation, which is incorrect according to the website. Is there some factor I'm neglecting?

Rho is the density of the fluid, not the pressure, so I'm not sure why you are using 1.5e5 in the equation. Also, pay attention to units when you are doing your computation (doing so would have revealed this error).
 

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