Change integration limits for cylindrical to cartesian coord

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To change the integration limits from cylindrical to Cartesian coordinates, the integral of a function f(r) must be expressed in terms of x and y using the relationship r=√(x^2+y^2) and the differential area element as dx dy. The integration order needs to be specified, with the limits for x determined as x=-√(b^2-y^2) and x=√(R^2-y^2). However, the conversion from a one-variable integral to a two-variable integral is incorrect without proper adjustments. The correct approach involves using the transformation dx dy = r dr dφ to maintain the integrity of the integral.
MCB277
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Homework Statement


I want to change the integration limits of an integral in cylindrical to cartesian coordinates. For example the integral of function f(r) evaluated between b and R: ∫ f(r)dr for r=b and r=R (there is no angular dependence).

For write de function in cartesian coordinates, use r=√(x^2+y^2) and rdr=dxdy, then, I should indicate an integration order for x and y.

Homework Equations


r=√(x^2+y^2)
∫ f(x,y)dx dy for x=? and y=?

The Attempt at a Solution



If I integrate in x first, de limit of integration should be x=-√(b^2-y^2) and x=-√(R^2-y^2), but for "y", what happens?.

Thanks
 
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MCB277 said:
dr=dxdy
This is not correct. You cannot rewrite a one-variable integral into a two-variable integral like that. What you are looking for is ##dx\,dy = r\, dr\, d\varphi##.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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