Changing rectangular coordinates to polar coordinates ?

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To convert the boundaries defined by X=0, Y=0, x+y=1, and x+y=2 into polar coordinates, the equations X=0 and Y=0 translate to theta=pi/2 and theta=0, respectively. The challenge lies in converting the linear equations x+y=1 and x+y=2 into polar form. By substituting the polar coordinate equations x=r cos(theta) and y=r sin(theta) into these linear equations, one can derive the corresponding r values for the integration bounds. This approach clarifies the conversion process and allows for successful integration in polar coordinates. Understanding these transformations is essential for solving problems involving areas in polar coordinates.
rclakmal
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Hey i know that we can change it by using
r^2=X^2+y^2
and
tan(theta)=y/x;

but finding some problems in converting the area surrounded by
X=0; Y=0; x+y=1; x+y=2 to polar coordinates .

yr of course you can convert X=0 to theta=pi/2 and Y=0 to theta=0;


But i don't how to convert other 2 boundaries to polar coordinates.Can anyone help me
 
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Polar coordinates are given by x=r \cos \theta, y=r \sin \theta, r=x^2+y^2.
 
You can convert rectangular coordinates to polar form, and vice versa. Here is a summary of the conversion formulas going both ways.

Convert rectangular to polar

<br /> r = \pm \sqrt{x^2 + y^2}
\theta = tan^{-1} (y/x)

Convert polar to rectangular
x = r cos(\theta)
y = r sin(\theta)
 
yr of course i know those two equations !and i have been successful in converting two boundaries of the region .But my problem is how to convert X+Y=1 and X+Y=2 to polar coordinates.
I hope u guys got my question !
 
Then use those equations. Substitute them into x+y=1 and x+y=2 and solve for r to get the upper and lower bounds for the r integration in terms of theta.
 
ah ok i got it now thanks !
 
rclakmal said:
yr of course i know those two equations
If you look carefully, you'll see that there are four equations.
 

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