How Do You Calculate Average Charge Density in a Cylinder?

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SUMMARY

The discussion focuses on calculating the average charge density in a cylinder with a charge distribution defined by ρ = Cr², where C is a constant and r is the radial distance. To derive the average charge density, one must integrate the charge distribution over the volume of the cylinder using cylindrical coordinates. The total charge Q is computed as Q = 4CπR⁵ / 5 after performing the necessary volume integrals. The average charge density is then found by dividing the total charge by the volume of the cylinder.

PREREQUISITES
  • Cylindrical coordinates
  • Integration techniques
  • Understanding of charge density
  • Volume calculations for cylinders
NEXT STEPS
  • Learn about volume integrals in cylindrical coordinates
  • Study the concept of charge density in electrostatics
  • Explore the derivation of average values in physics
  • Review applications of integration in electromagnetism
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Students in physics or engineering, particularly those studying electromagnetism and charge distributions, will benefit from this discussion.

Roodles01
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Homework Statement


A cylinder of radius a and length l has charge distribution

ρ=Cr2
where C is a constant and r is radial distance in cylindrical coordinates.
Derive an expression for the average charge density within the cylinder.

Homework Equations


Well, charge density given is within the volume, I think.
So for a point on the axis of the cylinder should be ρ divided by the length shouldn't it? Or is that being too simple?

The Attempt at a Solution



ρ = Cr2 / l
[/B]
Can someone confirm this or point me in the right direction, please.
 
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First you need to integrate the distribution over the cylinder to find the total charge.
 
∫ Cr2 dr

C ∫ r2 dr (0 < l < L)

CL3/3
 
The radius 0 < r < a .
The length L.

You need to integrate over the VOLUME of the cylinder to find the total charge in the volume. I advise working in cylindrical co-ordinates. where dV = rdrd\theta dz
 
s ρ(r) dV = Q

∫ Cr2 * 4πr2 dr = 4Cπ ∫ r4 dr

so
Q = 4CπR5 / 5
 
You need to integrate over the cylinder.

\int dV \ = \iiint rdrd\theta dz\ = \int_{0}^{L} dz \ \int_{0}^{2\pi}d\theta \int_{0}^{a}rdr This is the volume integral for a cylinder and as you can see, doing the integral gives the volume of a cylinder of radius, a, and length, L. But since your integrating a function over this volume, you want
\int \rho(r) dV You can split the integral similarly to find the total charge.
 
Last edited:

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