Charge inside a spherical conducting shell

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SUMMARY

When a charge is placed inside a spherical conducting shell, the total electric field inside the conducting material is zero due to the redistribution of charges on the shell's inner surface. However, the electric field in the empty space within the shell is not zero. If a charge is moved through a hole in the shell, the work done is not zero because the electric field in that region is not canceled out by the conducting material. Conversely, moving the charge through the conducting material itself results in zero work done due to the absence of an electric field.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with the properties of conductors in electrostatic equilibrium
  • Knowledge of electric potential and potential energy concepts
  • Basic principles of charge distribution in conductors
NEXT STEPS
  • Study Gauss's Law and its application to spherical conductors
  • Explore the concept of electric potential and its relationship to electric fields
  • Learn about energy conservation in electrostatics
  • Investigate the effects of introducing holes in conductive materials on electric fields
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zeeva
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If a charge is placed inside a spherical conducting shell, is the total electric field inside it zero? I am thinking that if the charge is positive, then the conducting shell will have an equal amount of negative charge on its inner surface, therefore the E field should be zero inside, right?
 
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You mean the electric field in the space filled by the conducting material? In that case you're right, it would be zero. That's pretty general, actually: any space filled with conducting material will have zero electric field, because if the electric field were nonzero, it would push around electrons inside the conductor until they canceled out the external field.

Of course the E field in the empty space inside the shell would not be zero.
 
Does that mean that if the shell had a hole through it and we wanted to move the charge from the inner radius to the outer radius, the work would be zero?
 
It would be better to use energy considerations here. The value of potential energy would be different in the initial and the final configurations.

Work done=Change in Potential Energy
 
zeeva said:
Does that mean that if the shell had a hole through it and we wanted to move the charge from the inner radius to the outer radius, the work would be zero?
Not if you move the charge through the hole. The space of the hole is not filled with conducting material, so there's no reason the electric field inside it would be zero.

Of course, if you move the charge through the metal itself, and not through the hole, then the work done would be zero.
 

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