Surface charge density of a conducting spherical shell

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Samanko
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The textbook says
' A conducting sphere shell with radius R is charged until the magnitude of the electric field just outside its surface is E. Then the surface charge density is σ = ϵ0 * E. '

The textbook does show why. Can anybody explain for me?
 
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Is this homework?

In any case apply Gauss's law with gaussian surface a sphere that has the same center as the charged sphere and radius ##R+dr## where ##dr## infinitesimal. You should get as result an equation that relates E (the electric field at distance R+dr) and ##\sigma## and ##R+dr##. Take the limit of that equation as ##dr\to 0## and you end up with the equation displayed in your textbook.
 
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Equation σ = ϵ0 * E applies to conductive surfaces, regardless of their shapes

E-Field 1.jpg
 
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Delta2 said:
Is this homework?

In any case apply Gauss's law with gaussian surface a sphere that has the same center as the charged sphere and radius ##R+dr## where ##dr## infinitesimal. You should get as result an equation that relates E (the electric field at distance R+dr) and ##\sigma## and ##R+dr##. Take the limit of that equation as ##dr\to 0## and you end up with the equation displayed in your textbook.
Got it! Thanks.
 
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