Charged particle in a magnetic field

[Nivlac2425]

Homework Statement

A charged particle with a charge-to-mass ratio of 5.7 x 10^8 C/kg travels on a circular path that is perpendicular to a magnetic field whose strength is .72 T.
How much time does it take for the particle to make one revolution?

Homework Equations

(Magnetic)F = qvB = (Centripetal)F = (mv^2)/r

The Attempt at a Solution

I can produce an equation for the velocity of the particle using the above equation, but how would one find the time that it takes? Hmmm, I know this is probably right in front of my face, but I'm just not seeing it... time...hmm...any hints?

Thank you everyone for even trying to help me out!

 

[LowlyPion]

v = ω*r = (2*π /T)*r

 

[Nivlac2425]

Hahaha! Oh, how did I not think of that! Such a fundamental idea didn't cross my mind!
Thank you for helping out, I'll have to think clearly next time!