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Why during charging a battery the terminal Potential Difference becomes greater than the EMF?
How what? Please be specific when posting questions, or you will confuse people, and more importantly you will confuse me!Well to be more specified.I wanted to ask HOW..
I think the charger is simply set up to apply a greater voltage than the battery produces.Sorry for inconvenience...I wanted to ask:
How the potential difference becomes greater than EMF?
The model for most batteries is of an "ideal" voltage source in series with a resistor. It's that resistor that you need to consider.Well to be more specified.I wanted to ask HOW..