Check if answers are right on my review? (vector eqns, curvature )

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Hi these are questions from my test review that i am unsure of, i posted question and my answer

if you can tell me if I've gotten right answer that would be much appreciated!

Let C be the curve with the equations [itex]x = 2 - t^3, y = 2t - 6, z = \ln(t)[/itex]

Find the point where C intersects the xz-plane
Find parametric equations of the tangent line at (1,-4,0)

ans:
[itex] (-25,0,ln(3))[/itex]

[itex] x = 1 - 3t, y = -4 + 2t, z = t[/itex]

=========================================find an equation of the osculating plane of the curve [itex]x = \sin{5t}, y = \sqrt{5}t, z = \cos{5t}[/itex] at the point [itex](0,\pi \sqrt{5}, -1)[/itex]

ans:

[itex]-\frac{\sqrt{6}}{6} \cos{5t} x + \frac{\sqrt{30}}{6} ( y - \frac{\pi \sqrt{5}}{5}) + \frac{\sqrt{6}}{6} \sin{5t} (z + 1) = 0[/itex]=========================================Find the curvature of the curve [itex]y = 2 \sqrt{x}[/itex] at the point [itex](3, 2\sqrt{3})[/itex]

ans:

[itex]\kappa(3) = \frac{1}{16}[/itex]

=========================================

An athlete throws a shot at an angle of 45 degrees to the horizontal at an initial speed of 36 ft/sec. It leaves his hand 4 feet above the ground.

Where is the shot 2 seconds later?
Where does the shot land?

ans:

[itex](36\sqrt{2} ft, 36\sqrt{2} - 15.6 ft)[/itex]

x = 132ft

=========================================Find the tangential and normal components of the acceleration vector of a particle with position function [itex]r(t) = \cos{t} i + \sin{t} j + \sqrt{15}t k[/itex]ans:

at = 0
an = 1==========================================

True/false...

The curve [itex]r(t) = <0,t^2, 4t>[/itex] is a parabola

T

The curve with the vector equation [itex]r(t) = t^3 i + 2t^3j + 3t^3 k[/itex] is a line

T

The binormal vector is [itex]B(t) = N(t) x T(t)[/itex]

F (opposite direction... not sure about this one though)

If curvature [itex]\kappa(t) = 0[/itex] for all t, the curve is a straight line

T

The curve [itex]r(t) = <2t, 3 - t, 0 >[/itex] is a line that passes through the origin.

F

If [itex]|r(t)| = 1[/itex] for all t, the r'(t) is orthogonal to r(t) for all t

T

if u(t) and v(t) are differentiable vector functions then [itex]\frac{\delta}{\delta t}[u(t) x v(t)] = u'(t) x v'(t)[/itex]

FI'm pretty sure the majority of these are right. the physics one and oscillating plane are the ones I am kind of unsure of! thanks for any help i have test soon!
 
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oreosama said:
Hi these are questions from my test review that i am unsure of, i posted question and my answer

if you can tell me if I've gotten right answer that would be much appreciated!

Let C be the curve with the equations [itex]x = 2 - t^3, y = 2t - 6, z = \ln(t)[/itex]

Find the point where C intersects the xz-plane
Find parametric equations of the tangent line at (1,-4,0)

ans:
[itex] (-25,0,ln(3))[/itex]

[itex] x = 1 - 3t, y = -4 + 2t, z = t[/itex]

=========================================


find an equation of the osculating plane of the curve [itex]x = \sin{5t}, y = \sqrt{5}t, z = \cos{5t}[/itex] at the point [itex](0,\pi \sqrt{5}, -1)[/itex]

ans:

[itex]-\frac{\sqrt{6}}{6} \cos{5t} x + \frac{\sqrt{30}}{6} ( y - \frac{\pi \sqrt{5}}{5}) + \frac{\sqrt{6}}{6} \sin{5t} (z + 1) = 0[/itex]
This can't be correct. There cannot be a "t" in the equation.

=========================================


Find the curvature of the curve [itex]y = 2 \sqrt{x}[/itex] at the point [itex](3, 2\sqrt{3})[/itex]

ans:

[itex]\kappa(3) = \frac{1}{16}[/itex]

=========================================

An athlete throws a shot at an angle of 45 degrees to the horizontal at an initial speed of 36 ft/sec. It leaves his hand 4 feet above the ground.

Where is the shot 2 seconds later?
Where does the shot land?

ans:

[itex](36\sqrt{2} ft, 36\sqrt{2} - 15.6 ft)[/itex]

x = 132ft

=========================================


Find the tangential and normal components of the acceleration vector of a particle with position function [itex]r(t) = \cos{t} i + \sin{t} j + \sqrt{15}t k[/itex]


ans:

at = 0
an = 1


==========================================

True/false...

The curve [itex]r(t) = <0,t^2, 4t>[/itex] is a parabola

T

The curve with the vector equation [itex]r(t) = t^3 i + 2t^3j + 3t^3 k[/itex] is a line

T

The binormal vector is [itex]B(t) = N(t) x T(t)[/itex]

F (opposite direction... not sure about this one though)

If curvature [itex]\kappa(t) = 0[/itex] for all t, the curve is a straight line

T

The curve [itex]r(t) = <2t, 3 - t, 0 >[/itex] is a line that passes through the origin.

F

If [itex]|r(t)| = 1[/itex] for all t, the r'(t) is orthogonal to r(t) for all t

T

if u(t) and v(t) are differentiable vector functions then [itex]\frac{\delta}{\delta t}[u(t) x v(t)] = u'(t) x v'(t)[/itex]

F


I'm pretty sure the majority of these are right. the physics one and oscillating plane are the ones I am kind of unsure of! thanks for any help i have test soon!