Circuit Analysis: Problem 4 - Obtain Current Through Galvanometer

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SUMMARY

The discussion centers on calculating the current through a Galvanometer in a Wheatstone bridge configuration, specifically problem 4. The participant applied a delta-Y transformation and calculated the equivalent resistance (Req) to be 32.4675Ω, leading to a current (I) of 0.4927 A. However, another participant pointed out that applying the delta-Y transformation may eliminate the resistor through which the current is being calculated, indicating a potential error in the approach.

PREREQUISITES
  • Understanding of Wheatstone bridge circuits
  • Knowledge of delta-Y transformation in circuit analysis
  • Familiarity with Ohm's Law (I = V/R)
  • Basic principles of electrical resistance
NEXT STEPS
  • Review the principles of Wheatstone bridge analysis
  • Study delta-Y transformation techniques in circuit theory
  • Practice calculating equivalent resistance in complex circuits
  • Explore common mistakes in circuit analysis and how to avoid them
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Electrical engineering students, circuit analysis practitioners, and anyone looking to deepen their understanding of Wheatstone bridges and current calculations in electrical circuits.

cooper607
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Homework Statement



problem---4
(5 marks) Obtain the current through the Galvanometer G, having a resistance of 14Ω, in
the Wheatstone bridge shown in Fig-4

Homework Equations



i know the delta-Y transformation and applied it, i found out the R (eq) to be 32.4675ohm

The Attempt at a Solution


I=V/R= 0.4927 A
someone please check the answer of problem no 4 and let me know if its right or wrong
regards
 

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cooper607 said:

Homework Statement



problem---4
(5 marks) Obtain the current through the Galvanometer G, having a resistance of 14Ω, in
the Wheatstone bridge shown in Fig-4

Homework Equations



i know the delta-Y transformation and applied it, i found out the R (eq) to be 32.4675ohm



The Attempt at a Solution


I=V/R= 0.4927 A
someone please check the answer of problem no 4 and let me know if its right or wrong
regards

Doesn't look right to me.

If you apply a Δ-Y transformation, won't you transform-away the very resistor you wish to find the current through?
 

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