1. The problem statement, all variables and given/known data http://imageshack.us/a/img832/1651/homeworkprobsg32.jpg [Broken] At t= 0, the switch is opened. Calculate the current i(t) for t>0 2. Relevant equations V(t) = L* dI/dt V = IR I = V/R voltage division, current division, KCL, KVL 3. The attempt at a solution Not so experienced with inductors but, at the beginning with the switch connecting: voltage division: V across right branch: (12Ω/14Ω)*36V V = 30.85V so this must be the total voltage across the branch with the 6Ω and 2H Voltage across 2Ω = 36V - 30.85V = 5.142V I across 2Ω resistor = 5.142V/2Ω = 2.571A, and 2.571A enters the parallel branches so this is the total current combined through the parallel branches I know now that the voltage across an inductor is 0 if the current does not change so with that and current division: I = (12/18)(2.571A) = 1.714A through the inductor branch with the switch connected at the beginning and then the current through the other branch is 0.857A at the beginning. My problem I think is calculus related again since V(t) = L* dI/dt is the only equation I know for an inductor, I try to set up a problem going like v(t) = 2H*dI(dt) + 6Ω(1.714A) but not sure and couldn't the current be 0 if the switch is opened?