The discussion focuses on analyzing the forces acting on a ball rolling down a quarter-circle ramp with a radius of 0.5m and a weight of 25g. The key equations mentioned include gravitational potential energy (mgh), kinetic energy (1/2 mv²), and centripetal force (mv²/R). Participants emphasized the importance of Newton's Laws, particularly the third law, in understanding the interaction between the ball and the ramp. The forces exerted by the ramp on the ball and vice versa are central to solving the problem, with clarification needed on the distinction between centripetal force and gravitational force.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics and forces in circular motion, as well as educators seeking to enhance their understanding of energy conservation and force interactions.
That force, in which body is acting? Are they components or your equatin is a vector equation. Try to explain your approach in words so we can help you.tbear said:I used Fnet = Fcircular+ Fg
Where is your attempted solution?tbear said:Homework Statement
A ball rolls down a ramp which forms a quarter circle of radius 0.5m. The ball weighs 25g. The bottom of the ramp is 1.5m above the floor. Assume no friction between the ball and the ramp. Assume no air resistance.
- what is the force exerted by the ramp on the ball?
- whatis the force exerted by the ball on the ramp?
Homework Equations
The Attempt at a Solution
What do you mean by Fcircular? If you mean centripetal force, that is not an applied force. It is the radial component of the resultant force, i.e. the component of the resultant force that is normal to the velocity. So you would not add it to Fg.tbear said:I used Fnet = Fcircular+ Fg