Circular Motion and tangential acceleration Problem

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Homework Help Overview

The problem involves a car moving on a circular track with a specified radius and tangential acceleration. The original poster seeks to determine the frictional force acting on the car after a certain time, given that the car is not skidding.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the identification of forces acting on the car and the calculation of distance and velocity using kinematic equations. There is also a focus on how to correctly calculate the frictional force based on the car's motion.

Discussion Status

Some participants have provided calculations for distance and velocity, while others have suggested considering both tangential and radial components of acceleration when determining the frictional force. There is an ongoing exploration of the correct approach to combine these components.

Contextual Notes

Participants are working under the assumption that the car is not skidding, and there is a focus on the role of friction in providing both tangential and radial acceleration. The mass of the car and the parameters of the motion are specified, but there may be uncertainties regarding the correct application of vector addition for the accelerations.

animesh27194
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A car starts moving on a circular track of radius 100m from rest at t=0. The tangential acceleration of the car is 0.1m/s2
Then find out the frictional force acting on the car at t=10s. It is given that the car is not skidding during this period and the mass of the car is 10[tex]\sqrt{2}[/tex].


I got that the distance traveled after 10 seconds as 5m and the velocity of the car at the end of 10 seconds as 1m/s

But how do i proceed after that? :confused:
 
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Start by identifying the forces on the car. Also, what is the acceleration of the car?
 
I treid solving the problem, but I don't know if it is correct...

Using the given tangential acceleration, i found out the distance after 10 seconds and thereby, its velocity.

s = ut+(1/2)at2
s = (1/2)(0.1)(100)
s= 5m

Also, v2 = u2 + 2as
v2 = 2(0.1)(5)
Hence, velocity at t=10s is 1m/s

Using this value of v in the formula frictional force = (mv2)/r
Here, m=10[tex]\sqrt{2}[/tex]
v=1 m/s
r=100m

Solving this, I get fictional force as 0.142 Newton.

Is this right?:redface:
 
animesh27194 said:
I treid solving the problem, but I don't know if it is correct...

Using the given tangential acceleration, i found out the distance after 10 seconds and thereby, its velocity.

s = ut+(1/2)at2
s = (1/2)(0.1)(100)
s= 5m

Also, v2 = u2 + 2as
v2 = 2(0.1)(5)
Hence, velocity at t=10s is 1m/s
This is correct, but you could have used v=u+at to find the speed of the car a little more directly.
Using this value of v in the formula frictional force = (mv2)/r
Here, m=10[tex]\sqrt{2}[/tex]
v=1 m/s
r=100m

Solving this, I get fictional force as 0.142 Newton.

Is this right?:redface:
Almost. You've found one component of the frictional force. The tangential acceleration of the car is also the result of friction between the tires and the road.
 
So, should i add the radial and the tangential acceleration to get the total acceleration?
And I multiply that with the mass of the car to get the frictional force?
 
Yes, but remember that the components are vectors, so you need to add them vectorially to get the total acceleration.
 

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