one end of a light inelastic string is attached to a point A vertically above a point O on a smooth horizontal plane and at a height h above it. The string carries a particle P of mass m at its other end. WHEN JUST TAUT the string is inclined to the vertical at an angle S(adsbygoogle = window.adsbygoogle || []).push({});

if P moves in a horizontal circle,centre O,with speed v,show that

v^2<= hg tan^2 s

im reading this as the particle is on the smooth plane,as the circle centre is O,so my equations of motion are,with T=tension,r=rad of circle,R= reaction force

R+Tcos S-mg=0

Tsin S=mv^2/r

i know r=htan S

i know at speed V string is just taut,but putting T=0 makes no sense, so how to proceed?if i put T>0 i still need to get rid of the reaction force.

regarding the just taut part. on another question i had 2 strings attached to a particle at one end, and the other ends of the strings were attached at points in a vertical line. the paricle moved in circle at a speed which just made strings taut. to do the question i had to let the tension in the bottom string = 0. so what does just taut mean?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Circular motion/conical pendulum?

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