Circular Motion of a Car: Finding Friction Coefficient

AI Thread Summary
To determine the static friction coefficient required for a car to navigate a flat curve at 60 km/h, the centripetal force must equal the frictional force. The relevant equation is centripetal acceleration, given by v^2/r, where v is the speed in m/s and r is the radius of the curve. After converting the speed to 16.67 m/s and using a radius of 150 m, the calculation leads to a friction coefficient of approximately 0.189. Participants in the discussion emphasize the importance of unit conversion and applying Newton's second law correctly. Overall, the focus is on understanding the relationship between centripetal force and static friction in circular motion.
vitesse86
Messages
8
Reaction score
0

Homework Statement



I have a general question about circular motion of a car on a flat curve.
What must the static friction koefficient be if the car can make the swing by 60km/h?

Thank you,

Homework Equations



- We have to follow Newtons 2nd law.

- Fcentripetal = m*(v^2/r)

known stats:
r= 150m
v= 16,67m/s
g= 9,81



The Attempt at a Solution



mg = v2/r /g

m= v2/r*g

m= ((16,67*16,67)/(150*9,81))

m= 0.189


Need probably help here, not sure if I did do the equations right.
 
Last edited:
Physics news on Phys.org
Surely they must also have given you the radius of the track?

Have you any idea how to start the problem?
 
H_man said:
Surely they must also have given you the radius of the track?

Have you any idea how to start the problem?

Hi,

the radius is 150m.

Thanks,
 
Can someone help me please, need help as soon as possible.



, thanks!
 
vitesse86 said:

Homework Statement



I have a general question about circular motion of a car on a flat curve.
What must the static friction koefficient be if the car can make the swing by 60km/h?

Thank you,

Homework Equations





The Attempt at a Solution



So, frictional force equals to centripetal force, and also equals to that coefficient times normal force.

Find centripetal, and thus that's the frictional force (it's keeping the car in that circle)
and then
Fn.coefficient = Centripetal force
mass cancels out..
and
so
g.coefficient = centripetal acc..

hoping this would help
 
Last edited:
harmeet_angel said:
So, frictional force equals to centripetal force, and also equals to that coefficient times normal force.

Find centripetal, and thus that's the frictional force (it's keeping the car in that circle)
and then
Fn.coefficient = Centripetal force
mass cancels out..
and
so
g.coefficient = centripetal acc..

hoping this would help


Hi,
thanks for the help.
But can't you help me a little closer, I am pretty new to this and I am also a newbee.

Thanks,
 
Centripetal = v^2/r
v=60 km/hr -- convert this is m/s
r=150 m

g.Answer = (v^2/r)
Answer = (v^2/r).g

sounds like a weird answer.. perhaps me wrong
 
harmeet_angel said:
Centripetal = v^2/r
v=60 km/hr -- convert this is m/s
r=150 m

g.Answer = (v^2/r)
Answer = (v^2/r).g

sounds like a weird answer.. perhaps me wrong

Can somebody help us here, please honestly!
 
harmeet_angel said:
g.Answer = (v^2/r)

Thats it, just make sure you convert units and then divide by g
 
  • #10
turdferguson said:
Thats it, just make sure you convert units and then divide by g

My english are abit bad, can you please write down for me how to do this?

f_on_car_1.gif

use this as a helping figure.
 
Last edited:
  • #11
hmm.. ite

so,
the answer for your question is = (v^2/(r.g))
v=16.67 m/s
r=150 m
g= 9.81

and so answer = 0.189
 
  • #12
harmeet_angel said:
hmm.. ite

so,
the answer for your question is =
v=16.67 m/s
r=150 m
g= 9.81

and so answer = 0.189

Can you show me the calculations how u did come
to (v^2/(r.g)) ?

Sorry I am a very newbee, and need everything in with a big fork



please help someone.:frown:
 
  • #13
vitesse86 said:
Can you show me the calculations how u did come
to (v^2/(r.g)) ?

Since this is a homework question, no one will calculate the answer for you. In fact, harmeet has given you lots of help, considering the fact that you have done nothing yet.

How about filling in numbers 2 and 3 in the homework posting template. What do you know? e.g. Do you know the equation to calculate centripetal force?
 
  • #14
cristo said:
Since this is a homework question, no one will calculate the answer for you. In fact, harmeet has given you lots of help, considering the fact that you have done nothing yet.

How about filling in numbers 2 and 3 in the homework posting template. What do you know? e.g. Do you know the equation to calculate centripetal force?

You are right.

There, i did filling in, and did an attempt.

Was it right or?


thanks for any help,
 
Back
Top