Circular motion of a subway train

AI Thread Summary
A subway train rounds an unbanked curve at 67 km/h, and the problem involves calculating the radius of the turn using the angle of an unused strap at 15 degrees to the vertical. The relevant equation is F = ma = mv^2/r, leading to the relationship r = mv^2/(N sin 15 degrees). The normal force is expressed as N = mg cos 15 degrees, allowing for substitution into the radius formula. After calculations, the derived radius is found to be 475 m, which differs from the book's answer of 132 m. The discussion emphasizes the importance of unit conversion and correct application of trigonometric functions in solving the problem.
Cantworkit
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Homework Statement


A subway train rounds an unbanked curve at 67 km/h. An unused strap makes an angle of 15 degrees to the vertical. What is the radius of the turn. The book answer is 132 m.


Homework Equations


F = ma = mv^2/r


The Attempt at a Solution


A free-body diagram shows a normal force pointing up 75 degrees from the horizontal axis. An mg force points down along the y axis.

Along the x-axis N sin 15 degrees = mv^2/r.

r = mv^2/N sin 15 degrees.

Along the y-axis N = mg cos 15 degrees.

Substituting, r = mv^2/mg sin 15 degrees/cos 15 degrees = v^2 / g tan 15 degrees

r = (67)^2 km^2/ H^2 / 9.8 m/s^2 / 3600 s^2/ h^2 * 1000 m/km / .268 = 475 m
 
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Cantworkit said:
A free-body diagram shows a normal force pointing up 75 degrees from the horizontal axis. An mg force points down along the y axis.

Along the x-axis N sin 15 degrees = mv^2/r.

r = mv^2/N sin 15 degrees.
Good.

Along the y-axis N = mg cos 15 degrees.
You mean: N cos 15 degrees = mg

Substituting, r = mv^2/mg sin 15 degrees/cos 15 degrees = v^2 / g tan 15 degrees
Good.

r = (67)^2 km^2/ H^2 / 9.8 m/s^2 / 3600 s^2/ h^2 * 1000 m/km / .268 = 475 m
First convert 67 km/h to m/s.
 
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