Clarification about conservation of Energy/Momentum

  • Thread starter Thread starter GoodGuyGoku
  • Start date Start date
  • Tags Tags
    Conservation
AI Thread Summary
Kinetic energy is conserved only in perfectly elastic collisions and when no external forces act on an object, but this does not mean it is conserved in all scenarios without forces. Linear momentum is conserved whenever there are no external forces, regardless of whether kinetic energy is conserved. Angular momentum conservation depends on the net torque being zero, which can be determined by calculating the torque rather than assuming it based on rotation. The misconception that no rotation implies no torque is clarified; torque can exist even when an object is not rotating. Understanding these principles is crucial for accurately applying the concepts of energy and momentum conservation in physics.
GoodGuyGoku
Messages
1
Reaction score
0
Hello,

I'm having some difficulties keeping when Linear/Angular Momentum and Kinetic Energy are conserved straight.

So far I believe that Kinetic energy is conserved when no outside/non-conservative forces are acting on an object. It is conserved only in perfectly elastic collisions, which only occur at the atomic level(?) Then it decreases in inelastic collisions and increases in explosions.

Linear momentum is conserved when Kinetic Energy is conserved, ie, no outside forces acting on the object and in all types of collisions.

Angular momentum is conserved when the net torque acting on an object is 0.
Here's my big question on this one, how do I know when the net torque is 0? I believe that torque is the tendency of an object to rotate, so when there's no rotation is there no torque?

I just need a little bit of clarification on all of these.


Thank you so much for your help!
 
Physics news on Phys.org
So far I believe that Kinetic energy is conserved when no outside/non-conservative forces are acting on an object.
That's not true. Kinetic energy for a single particle without any internal structure is conserved if no force at all is acting on it, but that is a boring situation, the particle will go in a straight line.
Kinetic energy is also conserved in elastic collisions, without any additional forces.
which only occur at the atomic level(?)
Let's say atoms are a very common place to find elastic collisions. It is not exclusive, and not all atomic collisions are elastic, but that is a good approximation.
Linear momentum is conserved when Kinetic Energy is conserved, ie, no outside forces acting on the object and in all types of collisions.
That's way too narrow. Linear momentum is conserved when there is no outside force. It does not matter what happens internally.

Here's my big question on this one, how do I know when the net torque is 0?
Calculate torque, see if it zero.

I believe that torque is the tendency of an object to rotate
No
so when there's no rotation is there no torque?
No (and it would not even follow from the above statement if that would be true).
In particular, if you have a net linear force, there are always reference frames where the torque is not zero.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top