Classical Mechanics - Box sliding down a slope

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Discussion Overview

The discussion revolves around a specific problem from Thornton's Classical Dynamics regarding the equations of motion for a box sliding down a slope. Participants are examining the mathematical expressions related to the derivatives of velocity and the integration of velocity squared versus velocity.

Discussion Character

  • Technical explanation

Main Points Raised

  • One participant questions the placement of the factor of 2 in the derivative of velocity squared, suggesting it relates to the differentiation process.
  • Another participant explains that the derivative of velocity squared involves both the velocity and its acceleration, leading to the expression involving 2 times the velocity and acceleration.
  • Participants discuss why the integral involves v0 squared rather than v0, attributing this to the nature of the differential being integrated.
  • There is a clarification that the limits of integration are from 0 to v0 squared, not v0.

Areas of Agreement / Disagreement

Participants appear to agree on the mathematical reasoning behind the derivative and the integration process, but the discussion does not resolve whether there are alternative interpretations or if any assumptions are missing.

Contextual Notes

The discussion does not address potential limitations in the assumptions made regarding the definitions of velocity and acceleration or the context of the problem.

jinksys
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I'm on pg 56 of Thorton's Classical Dynamics book and I see this: Imgur Link

Two questions: 1) Where does the 2 go on the second to last equation. 2) Why v0^2 and not v0 on the integral?
 
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jinksys said:
I'm on pg 56 of Thorton's Classical Dynamics book and I see this: Imgur Link

Two questions: 1) Where does the 2 go on the second to last equation. 2) Why v0^2 and not v0 on the integral?
1)[itex]\frac{d}{dt}(\dot x ^2 )=2\dot x \ddot x[/itex].
2)I'm guessing it's because of the differential which is a differential of velocity squared.
 
fluidistic said:
1)[itex]\frac{d}{dt}(\dot x ^2 )=2\dot x \ddot x[/itex].
This is bcoz
[itex]\frac{d}{dt}(\dot x ^2 )=\frac{d}{d\dot x}(\dot x ^2 )*\frac{d}{dt}(\dot x)[/itex]
So,[itex]\frac{d}{dt}(\dot x ^2 )=2(\dot x)(\ddot x)[/itex]
 
jinksys said:
2) Why v0^2 and not v0 on the integral?
This is bcoz u r integrating [itex]{d}(\dot x<sup>2</sup>)[/itex] and not [itex]{d}(\dot x)[/itex].
So, the limits are 0 and v02.
 

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