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Kilo
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Here's the problem:
The minute hand is 8 mm long and the hour hand is 4 mm long. How fast is the distance between the tips of the hands changing at one o'clock?
It's from my calculus textbook (Stewart)
I want to find how fast the distance changes relative to time, not the angle between the hands.
I decided to use the law of cosines and then take the derivative of it:
d=distance between hands, d'= rate of change of the distance, [tex]\theta[/tex]=angle between hands, [tex]\theta[/tex]'=rate of change of the angle
2dd'=2*4*8*sin([tex]\theta[/tex])[tex]\theta[/tex]'
I can find d using law of cosines and angle [tex]\theta[/tex], but would it be okay to find [tex]\theta[/tex]' by saying:
the hour hand travels [tex]\pi[/tex]/6 per hour and the minute hand travels 2[tex]\pi[/tex] per hour...
[tex]\theta[/tex]'= 2[tex]\pi[/tex]-[tex]\pi[/tex]/6=11[tex]\pi[/tex]/6 per hour
I'm just not sure if that is how I should find [tex]\theta[/tex]'
Thank you!
The minute hand is 8 mm long and the hour hand is 4 mm long. How fast is the distance between the tips of the hands changing at one o'clock?
It's from my calculus textbook (Stewart)
I want to find how fast the distance changes relative to time, not the angle between the hands.
I decided to use the law of cosines and then take the derivative of it:
d=distance between hands, d'= rate of change of the distance, [tex]\theta[/tex]=angle between hands, [tex]\theta[/tex]'=rate of change of the angle
2dd'=2*4*8*sin([tex]\theta[/tex])[tex]\theta[/tex]'
I can find d using law of cosines and angle [tex]\theta[/tex], but would it be okay to find [tex]\theta[/tex]' by saying:
the hour hand travels [tex]\pi[/tex]/6 per hour and the minute hand travels 2[tex]\pi[/tex] per hour...
[tex]\theta[/tex]'= 2[tex]\pi[/tex]-[tex]\pi[/tex]/6=11[tex]\pi[/tex]/6 per hour
I'm just not sure if that is how I should find [tex]\theta[/tex]'
Thank you!
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