Closed tank and inverted manometer question

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A user seeks assistance with a physics problem involving a closed cylindrical tank filled with water and an inverted manometer system. The problem requires determining the pressure in the pipe at point B and the equivalent pressure head at the top of the dome, given specific parameters including pressure readings and fluid densities. The initial response suggests creating a sketch to clarify the positions of points A and B, which is essential for solving the problem. The discussion emphasizes the importance of visual aids in understanding fluid dynamics scenarios. Engaging with the community for guidance on these calculations is encouraged.
razerangel
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Hey guy this is my first post here. I am looking for a little bit of help with a past paper I've been looking over. I've had a look at it and I am drawing a blank due to being off ill when this was covered in class, if anyone would be so kind as to show me how to get started on this question I would be very greatful.

Homework Statement



A closed cylindrical tank filled with water (pwater= 1000kg/m3) has a hemispherical dome and is connected to an inverted piping system. The liquid in the top of the piping system has a relative density of 0.8 and the remaning parts of the system are filled with water. Given that the pressure gauge reading at A is 60kPa, determine:

i)the pressure in the pipe at B
ii) the equivalent pressure head, in mm of mercury (pmercury = 13,600 kg/m3) at the top of the dome

Thanks in advance if anyone can help me out here :)!
 
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Hi and welcome to PF.

Before we can get started, I think a sketch would be helpful so we know where A and B are and any other useful information.
 

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