Closed tank and inverted manometer question

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SUMMARY

The discussion centers on a fluid mechanics problem involving a closed cylindrical tank filled with water and an inverted manometer system. The tank has a hemispherical dome, and the liquid in the piping system has a relative density of 0.8. Given the pressure gauge reading at point A is 60 kPa, the task is to determine the pressure at point B and the equivalent pressure head in mm of mercury. A sketch of the system is recommended for clarity.

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  • Understanding of fluid mechanics principles
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  • Familiarity with relative density calculations
  • Ability to interpret manometer readings
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  • Learn how to calculate pressure differences using manometers
  • Explore the concept of equivalent pressure head conversions
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razerangel
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Hey guy this is my first post here. I am looking for a little bit of help with a past paper I've been looking over. I've had a look at it and I am drawing a blank due to being off ill when this was covered in class, if anyone would be so kind as to show me how to get started on this question I would be very greatful.

Homework Statement



A closed cylindrical tank filled with water (pwater= 1000kg/m3) has a hemispherical dome and is connected to an inverted piping system. The liquid in the top of the piping system has a relative density of 0.8 and the remaning parts of the system are filled with water. Given that the pressure gauge reading at A is 60kPa, determine:

i)the pressure in the pipe at B
ii) the equivalent pressure head, in mm of mercury (pmercury = 13,600 kg/m3) at the top of the dome

Thanks in advance if anyone can help me out here :)!
 
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Hi and welcome to PF.

Before we can get started, I think a sketch would be helpful so we know where A and B are and any other useful information.
 

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