bapowell said:
No, because the alignment involves mutlipoles corresponding to sub-horizon fluctuation modes.
Thanks for that terminology.
Dipole notes
A Google search on sub-horizon fluctuation modes returned this paper among others. While reading it from a layman perspective I noticed section V., and how it addresses the monopole and dipole anisotropy.
http://cosmologist.info/teaching/EU/notes_structure.pdf
Refer to Section V., page 15-16, and figure 4
The story is that, if all the photons came from a single, nearly-spherical surface ...
Please be sure to go to the linked page and look at figure 4 on page 16. I think they are starting with the premise that there was no anisotropy at the point of recombination, and so the dipole hemispherical asymmetry came about in the way the photons scattered, (or something, shrug). I would like to understand their explanation for the dipole. Is it all accounted for our solar system/galaxy motion relative to the rest frame?V. COSMIC MICROWAVE BACKGROUND ANISOTROPIES
Recombination is a relatively sudden event at redshift z ∼ 1100, so we can get a good qualitative handle on what we expect to see in the CMB anisotropies by considering all the CMB photons to come from a single nearly-spherical surface about us, where the universe suddenly transitions from being an opaque plasma to being mostly neutral hydrogen gas.
If we consider a photon propagating in a perturbed universe, integrating the geodesic equation for the conformal Newtonian gauge metric gives the energy today E(η0) in terms at the energy at a (conformal) time η (see the question sheet)
[Missing equation, wouldn't copy over from paper]
to linear order in the perturbations. Here the integral is along the photon path; since the integrand is already first order, the integral can be taken to be along the unperturbed (background, zeroth order) photon path. What we mean by “along the photon path” is that in the integrand Ψ and Φ are evaluated at the position the photon had at time η, i.e. Φ(x, η) = Φ(x0 + (η0 − η)nˆ, η) where x0 is the location of the observer and nˆ is the unit vector in the direction in which we are observing the photon. The energies are those observed by an observer with no peculiar velocity.
At zeroth order this equation agrees with the FRW result, that E ∝ E0/a. The corrections in the perturbed universe are due to the difference in potentials between the point of emission and reception, Ψ(η) − Ψ0 (the net red/blue shift as the photon climbs out/falls into the potential wells at the two points), and an integrated contribution which is call the Integrated Sachs-Wolfe (ISW) effect. This reflects the net blue/red-shift as the photon falls into and falls out of the evolving potentials along the ...
[See figure 4 images on top of page 16]
(almost) uniform 2.726K blackbody
Dipole (local motion)
O(10-5) perturbations (+galaxy)
[Image caption]
FIG. 4: The observed CMB sky: almost uniform, with the monopole subtracted showing the O(10−3) dipole due to local motion, and with both the monopole and dipole subtracted to show the anisotropies (+ foreground contamination from our galaxy).
... line of sight. In a matter dominated universe Φ′ = Ψ′ = 0, so this term vanishes: there is an exact cancellation between the blue and red shifts as the photon falls into and climbs out of the potentials. However since there is dark energy at late time, this term is not zero, with the contribution from z 1 when dark energy becomes important being called the “late-time integrated Sachs-Wolfe effect”. For the CMB, where photons decoupled at recombination, there is also some evolution of the potentials near the start of the photon paths because recombination was not completely matter-dominated (there was still some contribution to the energy density from radiation).