Collapsing the wavefuntion to an Energy Eigenfunction?

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The discussion centers on the challenge of measuring the energy of a single particle immediately after it has collapsed to an energy eigenfunction. Participants note that traditional experiments often focus on position measurements, which can collapse the wavefunction to a delta function. It is suggested that particle colliders routinely measure energy, but the issue remains how to do so without first measuring position. The mass spectrometer is mentioned as one potential method for measuring energy independently of position. The conversation highlights the complexities of quantum measurement and the need for innovative experimental approaches.
mkarydas
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Is there an experiment that can measure the energy of a single particle so immediately after it has collapsed to one of the energy eigenfunctions?
The problem is that all experiments i can think of are about measuring the position of a the particle so we collapse it to its delta function. But how can someone experimentally measure the energy of a particle ?
 
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What's your question?

How someone measures experimentally the energy of a particle? - well its done all the time in particle colliders.

How one measures it immediately after - simply do the same experiment immediately after - of course if the measurement didn't destroy it.

Thanks
Bill
 
Last edited:
thats exactly my question..how does one measure the energy of a particle without measuring its position first?
 
mkarydas said:
thats exactly my question..how does one measure the energy of a particle without measuring its position first?

Mass spectrometer is one way - probably others as well.

Thanks
Bill
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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