Collision between two bodies with same mass

AI Thread Summary
In a collision between two bodies of equal mass, the conservation of linear momentum dictates that if mass m1 collides with stationary mass m2, m1 will come to rest while m2 moves with m1's initial velocity. The discussion highlights the misconception that the two bodies would stop being in contact once they reach the same speed during the collision. It clarifies that both bodies can remain in contact throughout the collision due to deformation, allowing them to transfer forces continuously. The interaction involves a compression phase where forces are exerted, followed by a decompression phase that facilitates the complete transfer of momentum. Understanding the dynamics of deformation during collisions resolves the initial confusion about contact and force transfer.
DarkFalz
Messages
71
Reaction score
0
Hello, its my first time in this forum, I've registered because sometimes i have some physics questions during my free times (maybe not the best free time "sports" xD).

The question is the following, according to the linear momentum conservation with elastic bodies, when a mass m1 with velocity v1 collides with a mass m2 which was stationary, mass m1 will become stationary and m2 will move with velocity v1.

The problem is that i just can't understand what is happening during the collision, from my naive point of view, when m1 collides with m2, it exerts a force on m2 because m2 is in m1 path, as such m1 will transfer is velocity to m2.

The problem is that I've heard that not just one force is exerted between the two bodies, and that the forces vary according to the following function:

col3.gif


That makes me wonder the following, in the beginning of the collision, let's say, until the maximum of the function, the mass m1 loses half its speed, and m2 gains half m1 speed, since half the total force has been exerted between the two bodies. if that's the case, at that point both bodies will have the same speed and won't be in contact anymore, so the collision would stop. What am i missing here? Where am i thinking wrong?

Thanks in advance
 
Physics news on Phys.org
DarkFalz said:
the mass m1 loses half its speed, and m2 gains half m1 speed, since half the total force has been exerted between the two bodies. if that's the case, at that point both bodies will have the same speed and won't be in contact anymore, so the collision would stop. What am i missing here? Where am i thinking wrong?
Why do you think they won't be in contact anymore?
My advice: go to the siding rail and see the collisions (watch bumpers!) between cars, as they are re-aranged
 
First of all, m1 will only end up stationary in the end if m1 = m2.

If the masses are perfectly rigid and the collision is perfectly elastic (which is what it sounds like you have in mind), your curve would have to be made infinitely thin and infinitely tall in such away that its integral is still the total force. Then your problems of them not being in contact anymore goes away.

The finite curve you posted is more realistic. It is the curve for two masses colliding that are deforming as they collide. In that case, they are in contact the whole time the force is exerted and this is made possible despite their different speeds because they are deforming properly to stay in contact.

In the picture below, you can tell that both objects involved in the collision are deforming upon impact so that they are in contact for the whole interaction despite being at different (and continually changing) speeds during the interactionhttp://www.popular-pics.com/PPImages/Deep-Impact-football.jpg .
 
Last edited by a moderator:
Oh, i understand now, since they compress, they remain in contact even after half the force has been transfered, with the decompression phase allowing for the rest of the force to be applied. Is that it?
 
Exactly!
 
Ok, i understand now, thanks a lot xD
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top