Collisions of molecules: Calculating Collision Rates in a Gas Box

[fredrick08]

[SOLVED] collisions of molecules..

Homework Statement

a 10cm^3 box contains nitrogen at 20degreeC. What is the rate of collisions on one wal of he box.

Homework Equations

kb=1.38x10^-23
1u=1.661x10^-27
molecular mass of N2=28u
avagadros number=6.02x10^23mol^-1
vrms=sqrt((3kbT/m))
rate of collisions=(1/2)(N/V)Av

The Attempt at a Solution

omg i got no idea where even start with this one... I am pretty sure i could do it if they gave me the mass of the gas or the number of molecules... but I am just stuck... y do they give me avagdros number? I am srry I am just really confused bout this one... anyone please help??

 

[fredrick08]

n=N/Na?? but i don't know n?

 

[gendou2]

Remember, an ideal gas (such as N₂) has a molar volume of 22,400 cubic centimeters per mole at STP (Avogadro's Law).

We know the volume of the box, so we know how many moles of ideal gas there are at 20°C, so we know how many molecules there are.

 

[fredrick08]

oh ok ty

 

[gendou2]

You're very welcome.
Once you're satisfied with the problem, please change the title to "[SOLVED] Collisions of molecules".
Good luck!