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Common source amplifier low frequency resonse

  1. Jul 31, 2016 #1
    Here's the amplifier in question:
    common source.PNG

    I'm not understanding this part:
    answer.PNG

    Why is Cs not included in the current divider ?
    To my understanding of current divider, It = Id+Io, where It is the current flowing through Rd
    So, Io = It*(1/Cs)/(1/Cc2)+RL
     
  2. jcsd
  3. Jul 31, 2016 #2
    But Cs is in series with Id current. Please explain to me how Cs affects Io.
     
  4. Jul 31, 2016 #3
    Yes, it's correct. I must have gotten confused somewhere but it's fine now
     
  5. Jul 31, 2016 #4
    Do you have any more qestion about this amp?
    1.1.png
     
  6. Aug 1, 2016 #5
    No, i'm good, thanks
     
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