Common source amplifier low frequency resonse

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Discussion Overview

The discussion revolves around the low-frequency response of a common source amplifier, specifically focusing on the role of the coupling capacitor Cs in the current divider analysis.

Discussion Character

  • Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions why Cs is not included in the current divider, stating their understanding of the current divider equation.
  • Another participant asserts that Cs is in series with the Id current and asks for clarification on how Cs affects Io.
  • A later reply acknowledges confusion but indicates that the issue is resolved for them.
  • Further replies inquire if there are any additional questions regarding the amplifier.

Areas of Agreement / Disagreement

The discussion shows some initial confusion regarding the role of Cs, but later replies suggest that at least one participant feels their understanding has improved. However, no consensus on the technical details is explicitly stated.

Contextual Notes

There may be limitations in the assumptions regarding the circuit configuration and the definitions of the currents involved, which are not fully explored in the discussion.

TheRedDevil18
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Here's the amplifier in question:
common source.PNG


I'm not understanding this part:
answer.PNG


Why is Cs not included in the current divider ?
To my understanding of current divider, It = Id+Io, where It is the current flowing through Rd
So, Io = It*(1/Cs)/(1/Cc2)+RL
 
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But Cs is in series with Id current. Please explain to me how Cs affects Io.
 
Jony130 said:
But Cs is in series with Id current. Please explain to me how Cs affects Io.
Yes, it's correct. I must have gotten confused somewhere but it's fine now
 
Do you have any more qestion about this amp?
1.1.png
 

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