Comparing the real (integer part) of a number.

  • Thread starter Thread starter mtayab1994
  • Start date Start date
mtayab1994
Messages
584
Reaction score
0

Homework Statement



Compare between E(x+y) and E(x)+E(y) for every real number x and y.

E() refers to the real integer part of the number.


The Attempt at a Solution



Well I know that we have to split it up into 3 cases. One for which both are positive, both negative, and one of them is negative. For example I know when we have x and y greater than 0 we get E(x+y)≥E(x)+E(y) because let's take x=1.5 and y=1.6 then E(1.5+1.6)= 3 and
E(1.5)+E(1.6)= 2. Can anyone help me come up with a proof for this?
 
Physics news on Phys.org
Anyone have any ideas.
 
Alright Thank You I came up with a proof from what i read on wiki.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top